Question

A body is dropped from a height h. calculate:a) The Time Taken by it the ground. b)The velocity of that sody on allodai reaching the geround. и​

Answer 1

Answer:-

We are given:-

s =hs=h

a = 10\frac{m}{s^{2} }a=10

s

2

m

( for easy calculations)

u=0\frac{m}{s}u=0

s

m

What we need to find:-

Time and final velocity

What we need to do:-

Let us use first equation of motion.

v=u+atv=u+at

Let us now plug in the values.

v=0+10tv=0+10t

By simplifying, we get

v=10tv=10t ------- 1

Now, let us use second equation of motion

s=ut+\frac{1}{2} at^{2}s=ut+

2

1

at

2

Let us now plug in the values.

h=0t+\frac{1}{2} (10)t^{2}h=0t+

2

1

(10)t

2

By simplifying, we get

\sqrt{\frac{h}{5} } =t

5

h

=t ------- 2

solving 1 and 2, we get

v=10\sqrt{\frac{h}{5} }v=10

5

h

∴ t=\sqrt{\frac{h}{5} }t=

5

h

and v=10\sqrt{\frac{h}{5} }v=10

5

h

.