Question

A body is dropped from a height h.If it travels a distance h÷3 during the last second of its fall then the time of travel(in seconds) is

Answer 1

Answer:

(3+√3)/2

Explanation:

let height be h and time taken by body to reach be t

then, we know,

h=1/2 gt^2

by question,

h/3 = 1/2 g(t-1)^2

1/3 ×1/2 gt^2 = 1/2 g(t-1)^2

after solving this we get,

t/(t-1) = √3

t(√3-1) = √3

t= √3/(√3-1)

after rationalising denominator and numerator

we get,

t= (3+√3)/2

Hence total time taken by the body is (3+√3)/2

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