Question

A body is dropped from a height h.Time taken to cover second half of the journey

Answer 1

the initial speed of the body,u=0

let ‘T’ be the total time taken by body to reach ground.

thus height covered:

H=1/2 gT2  

T=(2H/g)1/2

 

now let the time taken for 1st half of journey be ‘t’

distance covered th time t:

1/2H= 1/2gt2

t=(H/g)½

 

now time taken for second half of journey : T-t

= (2H/g)1/2 -(H/g)½

thus time taken for second half of journey is :  (H/g)1/2 * (2-1)1/2

= (H/g)1/2