a body is dropped from a height of 100m.At what height the velocity of the body will be equal to one half of velocity when it hits the ground
Answers
Answered by
24
75 m from ground. Final velocity=-20√5 it's half =-10√5 so from this ht = -25m which is 75 m from ground
Answered by
65
v^2-u^2=2as
v^2=2as(u=0)
v^2=2×10×100
v^2=2000
v=44.72m/s
half the vel. =44.72/2=22.36m/s
again
v^2-u^2=2as
v^2=2×10×s
22.36×22.36=20s
s=499.9/20
=500/20
=25m
dist above ground=100-25
=75m
v^2=2as(u=0)
v^2=2×10×100
v^2=2000
v=44.72m/s
half the vel. =44.72/2=22.36m/s
again
v^2-u^2=2as
v^2=2×10×s
22.36×22.36=20s
s=499.9/20
=500/20
=25m
dist above ground=100-25
=75m
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