Question

A body is dropped from a height of 100m . find its velocity while touching the grounds (given acceleration due to its gravity is 10ms^-2)

Answer 1

hey mate here is ur ans

given s = 100 m
v^ 2-u^2 = 2 as
v^ 2- 0 = 2 (10) 100
v ^2= 2000
v = 10√20 m/s

hope it help u

Answer 2

initial velocity = u = 0
let final velocity be v

now s which is the distance given is 200 m
so
.

we have
$200 = \frac{ {v}^{2} - 0 }{2 \times 10} = > 200 = \frac{ {v}^{2} }{20} \\ {v}^{2} = 20 \times 200 = 4000 \\ v = \sqrt{4000} = 63.24$

hope it helps