Physics, asked by Babuprakhar8444, 9 months ago

A body is dropped from a height of 320 m, The acceleration due to the gravity is 10 m/s^2. (a) How long does it take to reach the ground? (b) What is the velocity the velocity with which it will strike the ground?

Answers

Answered by Thakshayini
5

Answer:

hi there!!!

Explanation:

happy helping ❤️

refer to the picture....

Attachments:
Answered by GaganMS004
3

Explanation:

initial velocity u=0

height h=320m

g= -10m/s^2

h=ut+1/2at^2

320=0+1/2×-10t^2

320=-5t^2

time=8

final velocity=u +gt

=0+(-10)×8

= -80m/s

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