a body is dropped from a height of 490 m from the ground.It will hit the ground after what time?
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Answer:
after t = 10 s
Explanation:
h = 490 m
vi = 0 m/s
a = g
t = ?
using 2nd equation of motion
h = vi t + 1/2 gt²
490 = 0 + 1/2x 9.8 t²
t² = 490/4.9
t² = 100
t = 10 s
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