Question

A body is dropped from a height of 80m. 2 seconds later another body is dropped from the same

point. Find (a) height of second body from the ground as the first body reaches the ground (b)

velocity of the second body as the first one reaches the ground.​

Answer 1

Answer:

20m

Explanation:

S= ut + 1/2 at^2

80= 1/2 10 t^2

t^2 = 16

t= 4 sec

S= ut +1/2 at^2

S= 1/2×10×4

S = 20m