Question

Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.

Answer:
Mg: There are two valence electrons in Mg atom. Hence, the Lewis dot symbol for Mg is:


Na: There is only one valence electron in an atom of sodium. Hence, the Lewis dot structure is:


B: There are 3 valence electrons in Boron atom. Hence, the Lewis dot structure is:


O: There are six valence electrons in an atom of oxygen. Hence, the Lewis dot structure is:


N: There are five valence electrons in an atom of nitrogen. Hence, the Lewis dot structure is:


Br: There are seven valence electrons in bromine. Hence, the Lewis dot structure is:


Question 4.3:
Write Lewis symbols for the following atoms and ions:

S and S2–; Al and Al3+; H and H–

Answer:
(i) S and S2–

The number of valence electrons in sulphur is 6.

The Lewis dot symbol of sulphur (S) is

.

The dinegative charge infers that there will be two electrons more in addition to the six valence electrons. Hence, the Lewis dot symbol of S2– is

.

(ii) Al and Al3+

The number of valence electrons in aluminium is 3.

The Lewis dot symbol of aluminium (Al) is

.

The tripositive charge on a species infers that it has donated its three electrons. Hence, the Lewis dot symbol is

.

(iii) H and H–

The number of valence electrons in hydrogen is 1.

The Lewis dot symbol of hydrogen (H) is

.

The uninegative charge infers that there will be one electron more in addition to the one valence electron. Hence, the Lewis dot symbol is

.

Question 4.4:
Draw the Lewis structures for the following molecules and ions:

H2S, SiCl4, BeF2,

, HCOOH

Answer:
Please solve the questions.​

Answer 1

Answer:

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