Question

A body is dropped from a vertical height of 5m above the ground. Find the velocity with which it strikes the ground. (take g= 10m.s-² for this problem.)​

Answer 1

Answer:

The Velocity With Which The Body Hits The Ground is 10m/s

Explanation:

Initial Velocity(u) = 0m/sec

Acceleration Due to Gravity(g) = 10m/sec²

Distance(s) = 5m

Final Velocity = ?

Lets Use Third Equation Of Motion:-

${v}^{2} = {u}^{2} + 2as \\ = ) {v}^{2} = ( {0)}^{2} + (2 \times 10 \times 5) \\ = ) {v}^{2} = 100 \\ = )v = 10m.se {c}^{ - 1}$

Hope it helped

Answer 2

Answer:

Initial Velocity(u) = 0m/sec

Acceleration Due to Gravity(g) = 10m/sec²

Distance(s) = 5m

Final Velocity = ?

Lets Use Third Equation Of Motion:-

\begin{gathered} {v}^{2} = {u}^{2} + 2as \\ = ) {v}^{2} = ( {0)}^{2} + (2 \times 10 \times 5) \\ = ) {v}^{2} = 100 \\ = )v = 10m.se {c}^{ - 1} \end{gathered}v2=u2+2as=)v2=(0)2+(2×10×5)=)v2=100=)v=10m.sec−1

HOPE IT HELPS YOU!!!