Question

a body is dropped from the top of a building of height 40 meters find the velocity of the body on reaching the ground
( we use this formula
v²-u²=2as)
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Answer 1

Answer:

The Final Velocity is 28m/s

Given :

u (initial Velocity) = 0 (as it is dropped, it must be at rest at start)

h (height) = 40m

a OR g (acceleration due to gravity) = 9.8 m/s^2 (this is a constant value for acceleration due to gravity)

To find : v (final velocity)  

By using Third Equation, v² = u² + 2as

v² = 0 + 2 * 9.8 * 40

v² = 784  

v =  √784

v = 28m/s ( Answer )