A body is dropped from the top of a tower it acquires a velocity 20 ms -1 on reaching the ground calculate the height of the tower (take g=10ms-1)
Answers
Answered by
1
Answer:
20 meter
Explanation:
Use third equation of motion
2aS = vf²- vi²
2aS = 400 - 0
S = 400/2(10)
S = 400/20 = 20 meters
Mark me as brainliest
Similar questions