Question

A body is dropped from top of the tower and falls freely. The distance covered in nth is proportional is

Answer 1

Answer:

By the formula

Sn=u+a/2*(2n-1)

so,Sn is directly proportional to its initial velocity(u) and acceleration (a)of the particle.

Hope it helps.

Answer 2

Answer:

It is proportional to n^2

Explanation:

Given data :

Initial velocity (u) = 0 m/s

Acceleration (a) = -g m/s^2

Time(t) = n

s is the distance covered by the body.

Formula to be used :

According to Newton's equation of motion, we have :

$s = ut \: + \frac{1}{2} a {t}^{2}$

Obtaining Results :

$s = 0 + \frac{1}{2} ( - g) {n}^{2} \\ s = \frac{ - g {n}^{2} }{2}$

Now, g/2 is a constant,

Then, s is directly proportional to n^2 .

Hence, the distance covered is directly proportional to n^2 .

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