Question

A body is falling downwords 48 meter in 4 seconds .Calculate , what distance would it fall in 9 seconds . Given that, when a body falls , distance various directly as the square of time.​

Answer 1

Answer:

Let d be the distance from starting point and t be the time, then according to question

Let d be the distance from starting point and t be the time, then according to questiond=kt2

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10d=(16.1)100=1610 feets

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10d=(16.1)100=1610 feetsand distance for t=9

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10d=(16.1)100=1610 feetsand distance for t=9d=(16.1)81=1304.1 feets

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10d=(16.1)100=1610 feetsand distance for t=9d=(16.1)81=1304.1 feetsDistance fallen in 10th second =distance at t=10  - distance at t=9

Let d be the distance from starting point and t be the time, then according to questiond=kt2Given d=402.5 for t=5. So,402.5=k.52k=25402.5=16.1So,d=(16.1)t2For t=10d=(16.1)100=1610 feetsand distance for t=9d=(16.1)81=1304.1 feetsDistance fallen in 10th second =distance at t=10  - distance at t=9=1610−1304.1=305.9 feets

hope this will help you....