a body is falling freely under gravity. how much distance it falls during an interval of time between 1st and 2nd seconds of its motion.taking g=10.
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Using the kinematics equation, s = u.t + 1/2.a.t².
In t = 1sec, s = 1/2 (10) (1)² = 5m
In t = 2sec, s = 1/2 (10) (2)² = 20m
The distance travelled between the first and second seconds = 20 - 5 = 15m
In t = 1sec, s = 1/2 (10) (1)² = 5m
In t = 2sec, s = 1/2 (10) (2)² = 20m
The distance travelled between the first and second seconds = 20 - 5 = 15m
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