a body is falling from height h it takes t1 time to reach ground. the time taken to cover the first half of height is
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u=0
s=ut+(1/2)at^2 using this
h1=(1/2)at^2
(t)^2={2×h1/2}/a
t=√(a×h1)
Half distance=h1/2.
s=ut+(1/2)at^2 using this
h1=(1/2)at^2
(t)^2={2×h1/2}/a
t=√(a×h1)
Half distance=h1/2.
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