Question

A body is falling under gravity the distance covered in 1st ,2nd and 3rd second of its motion are

Answer 1

Distance covered in nth second of free fall is
S = u + a(n - 1/2)
= g(n - 1/2)

Distance covered in 1st second
S = g (1 - 1/2)
= g/2

Distance covered in 2nd second
S’ = g(2 - 1/2)
= 3g/2

Distance covered in 3rd second
S” = g(3 - 1/2)
= 5g/2

Ratio of distance covered ==> 1 : 3 : 5