A body is moving along a horizontal circular path with constant speed V what is the change in its velocity when it describes an angle theta
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Here it clear from the figure that change in magnitude of velocity is zero since particle moves with constant speed and speed at A equals to speed at B hence we can write
|vb| −|va| = v −v =0
now magnitude of change = here vb−→ = vsinθiˆ +vcosθjˆand va→ = vsinθiˆ −vcosθjˆnow vb→− va→ = vsinθiˆ +vcosθjˆ − vsinθiˆ +vcosθjˆ =2vcosθjˆ = 2vcos600jˆ = 2v×12jˆ = v jˆ∣∣vb→− va→ ∣∣ = ∣∣ v jˆ∣∣ = v
Hope it helped you out ^_^(^^)^_^(^^)
Thanks,(^^)
Here it clear from the figure that change in magnitude of velocity is zero since particle moves with constant speed and speed at A equals to speed at B hence we can write
|vb| −|va| = v −v =0
now magnitude of change = here vb−→ = vsinθiˆ +vcosθjˆand va→ = vsinθiˆ −vcosθjˆnow vb→− va→ = vsinθiˆ +vcosθjˆ − vsinθiˆ +vcosθjˆ =2vcosθjˆ = 2vcos600jˆ = 2v×12jˆ = v jˆ∣∣vb→− va→ ∣∣ = ∣∣ v jˆ∣∣ = v
Hope it helped you out ^_^(^^)^_^(^^)
Thanks,(^^)
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