Question

A body is moving along a straight line at 20 m/s and undergoes of -4m/S2 after 2 sec, it's speed will be

Answer 1

Answer:

12 m/s

Explanation:

As per the provided information in the given question, we have :

• Initial velocity (u) = 20 m/s
• Acceleration (a) = -4 m/s²
• Time taken (t) = 2 s

We are asked to calculate its speed after 2 seconds i.e, its final velocity.

By using the first equation of motion,

$\longrightarrow$ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

$\longrightarrow$ v = 20 + (-4)(2)

$\longrightarrow$ v = 20 + (-8)

$\longrightarrow$ v = 20 - 8

$\longrightarrow$ v = 12 m/s

∴ Velocity after 2 seconds will be 12 m/s.

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More Information :

Equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance

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