A body is moving in a vertical circle of radius R by means of a string. If the ratio of the maximum to the minimum speeds is √3:1, the ratio of the maximum to the minimum tensions in the spring is
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Answered by
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Answer:
Let v
1
and v
2
be the velocities at the lowest and the highest points.
∴
v
2
v
1
=
1
3
Conserving energy between the lowest and highest points gives
v
1
2
=v
2
2
+2gh
⇒3v
2
2
=v
2
2
+2gh
⇒v
2
2
=gh
⇒v
1
2
=3gh
h is distance between the lowest and the highest points which is 2r.
h=2r
Tensions at the lowest and highest point
T
1
=
r
mv
1
2
+mg
T
2
=
r
mv
2
2
−mg
⇒
T
2
T
1
=
v
2
2
/r−g
v
1
2
/r+g
⇒
T
2
T
1
=
2gr/r−g
6gr/r+g
⇒
T
2
T
1
=7/1
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