a body is moving with a constant acceleration Travels a distance 3 metre and 8 metre respectively in 1 second and 2 second calculate i) the initial velocity and ii) the acceleration of body
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we know s=ut+1/2a(t)^2
then 3=u.1+1/2a.(1)^2
6=2u+a••••••••(i)
and 8=u.2+1/2a (2)^2
8=2u+2a••••••(ii)
on solving (i) and (ii)
a=2
and u=2
therefore (i) 2 m/s
(ii) 2m/s^2
then 3=u.1+1/2a.(1)^2
6=2u+a••••••••(i)
and 8=u.2+1/2a (2)^2
8=2u+2a••••••(ii)
on solving (i) and (ii)
a=2
and u=2
therefore (i) 2 m/s
(ii) 2m/s^2
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