A body is moving with a uniform acceleration describes 10 m in the 2nd second and 20 m in the 4th second respectively. Calculate the distance moved by the body in the 5th second.
Answers
Answered by
1
v=s/t
v=10/2
v=5 m/s
s=v*t
s=(5*5)m
s=25m
v=10/2
v=5 m/s
s=v*t
s=(5*5)m
s=25m
Anonymous:
No check your answer. It will not be done by this method.
:)
but the answer is correct
Answered by
0
2 sec = 10 m
4 sec = 20 m
5 sec = ?
in one sec it goes 10/2 = 5 m
in 5 sec it goes =5 *5=24.....
have a nice day....
4 sec = 20 m
5 sec = ?
in one sec it goes 10/2 = 5 m
in 5 sec it goes =5 *5=24.....
have a nice day....
Your method is also wrong.
Plz check again... :)
That means its the probability or luck.
hahahaha ya
You're in 9th?
nope 10th
Similar questions