Question

A neutron having a mass of 1.67*10^-27 kg and moving at 10^8 m/s collides with a neutron at rest and sticks to it . Calculate the speed of combination. ( mass of neutron = 3.34*10^-27 )

Answer 1

Answer:

please mark as brilliant

Answer 2

Answer: The speed of the given combination is 3.33×10⁷m/s.

Explanation: Given data is :

$Mass\ of\ neutron=1.6\times 10^{-27}\ kg(M1)\\Speed\ of\ Neutron=10^{8}m/s(V1)\\Mass\ of\ deuteron=3.34\times 10^{-27} kg(M2)\\Speed\ of\ deuteron=0 m/s$

The combination has both neutron and deuteron sticked to each other and both will move with a common velocity(V)'

Here, conservation of linear momentum(COLM) will be applied:

$M1V1+M2V2=(M1+M2)V\\V=M1V1+M2V2/M1+M2$

$(1.67\times 10^{-27})\times 10^{8}+(3.34\times 10^{-27})0=(1.67+3.34)\times 10^{-27}\times V\\V=1.67\times 10^{-27}\times 10^{8}/5.01\times 10^{-27}\\V=3.33\times 10^{7}m/s$

There is a mistake in the question, neutron should collide with a deuteron since the mass of the deuteron is given in the question.

I have corrected it for you. Hope it helps.