Question

A body is moving with a velocity of 12m/sand it comes to rest in 18minutes, whatwas the acceleration?

Answer 1

Answer:

Verified Answer

SOLUTION :

velocity (u) = 12

m

S

distance (d) = 18m

final velocity (v) = 0

from second equation of motion

v² − u²=

- u² = 2(-a)s

>0²12²2(-a)(18)

=>

=> -144 = -36a

-144

-36

m

82

=> a =

.. ACCELERATION = 4 m/s²

[NOTE : HERE ACCELERATION IS

NEGATIVE BECAUSE IT IS IN THE

OPPOSITE DIRCTION OF MOTION. ANDFINAL VELOCITY IS O SINCE IT CAME TOREST]

Explanation:

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Answer 2

-4m/s²

this is your answer.