Question

A body is moving with an initial velocity of 5.6m/s. And uniform acceleration of 2.1cm/s^2 its velocity after 8s?

Answer 1

Explanation:

$u = 5.6$

$a = 2.1 \times {10}^{ - 2}$

$t = 8sec$

$a = v - u \div t$

$2.1 \times {10}^{ - 2} = 5.6 - v \div 8$

$5.6 - v = 2.1 \times 8 \times {10}^{ - 2}$

$5.6 - v = 16.8 \times {10}^{ - 2}$

$v = 5.6 - 0.168 = 5.43$