Math, asked by AsifAhamed4, 1 year ago

Find the zeroes of the quadratic polynomial

5 {x}^{2} - 2 \sqrt{5} x - 3 = 0

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Answered by Thatsomeone
5
\bold{\boxed{HEY!!!}}


Given quadratic equation => 5x² - 2√5x - 3 = 0


\underline{FACTORIZATION}


The product should be 15 and sum shoup be 2√5


Such pair is - 3√5 & √5


So


5x² + √5x - 3√5x - 3 = 0


=> √5.√5x² + √5x - 3√5x - 3 = 0


=> √5x(√5x + 1 ) - 3( √5x + 1 ) = 0


=> ( √5x + 1 )( √5x - 3 ) = 0


=> √5x + 1 = 0. or. √5x - 3 = 0


x = \frac{ - 1}{ \sqrt{5} } \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: \: \: x = \frac{3}{ \sqrt{5} } \\ \\ \\ so \: the \: roots \: of \: given \: quadratic \: equation \: are \: \frac{3}{ \sqrt{5} } \: and \: \frac{ - 1}{ \sqrt{5} }

AsifAhamed4: mate the answer is - 3root5 and root 5
AsifAhamed4: no no you r right am sorry
Thatsomeone: :-)
Answered by Anonymous
3
Hey it will help you....
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