Question

a body is moving with an initial velocity of 5m/s accelerates at 1m/s . it's velocity after 5second will be?

Answer 1

u=5
v=?
a=1
t=5

v=u+at
v=5+5{1}
v=10 m/s

Hope it helps you

Answer 2

We will start with calculating the final velocity:

Vf = Vi + a*t

Vf= Final Velocity (m/s)

Vi = Initial Velocity (m/s)

a = Acceleration (m/s^2)

t = Time (seconds)

We will plug in the appropriate information into the formula:

Vf = (6 m/s) + ((1.5 m/s^2)*(5 seconds))

Vf= (6 m/s) + (7.5)

Vf= (13.5 m/s)

We will calculate the distance covered:

D= (Vi)*(t) + (1/2)*(a)*(t^2)

D= distance (meters)

vi= initial velocity (m/s)

t=time (seconds)

a= acceleration (m/s/s or m/s^2)

D = (6 m/s)*(5 sec) + (1/2)*(1.5 m/s^2)*(5^2)

D= (30)+ (18.75)

D= (48.75 meters)

I hope this helps ! All the best !