Question

A body is moving with an initial velocity of 6m/s accelerates at 2m/s2 its velocity, after 10s ------

Answer 1

initial velocity = 6m/s

acceleration = 2m/s^2

time = 10 s

final velocity = v

a = (v-u)/t

2 = ( v - 6 )/10

2 * 10 = ( v - 6 )

v - 6 = 20  [ transposing ]

v = 20 + 6

v = 26 m/s

therefore, the final velocity of the body is 26 m/s

Answer 2

✰ Given -

• Initial Velocity (u) = 6 m/s
• Acceleration (a) = 2 m/s^2
• Time (t) = 10 sec

✰ To Find -

• Final Velocity (v) = ?

✰ Solution -

We know 1st Equation of Motion,

$✓ \: v = u + at$

Here,

• V = Final Velocity
• U = Initial Velocity
• A = Acceleration
• T = Time Period

Placing Values,

$⟶v = 6 + 2 \times (10)$

$⟶v = 6 + 20$

$⟶v = 26m/s$

⛬ Velocity after 10 sec is 26 m/s

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$✓ \: 3 \: Imp \: Equations \: Of \: Motion-$

1) $✓ \: v = u + at$

2) $✓ \: s = ut + \frac{1}{2} \: {at}^{2}$

3) $✓ \: {v}^{2} = {u}^{2} + 2as$

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