Question

a body is moving with uniform speed v in a circular path of radius R shown in figure . T is the period of revolution . the average velocity in the section ab is​

Answer 1

Answer:

We know that v=Rω=R(2π/T)=(2πR/T)⟹(R/T)=(v/2π)

The average velocity of the particle for the semicircular path is V

av

=2R/(T/2)=4R/T

Substituting the value of R/T from previous equation, we get V

av

=4(v/2π)=2v/π

Answer 2

Answer:

$4v \div t$

Explanation:

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