Physics, asked by yashwant05082006, 8 months ago

A body is moving with velocity "V" which varies with displacement as V = sqrt(4-2S)^S, its average acceleration after 6s is?

Answers

Answered by Anonymous
4

Explanation:

ANSWER

As shown in the given figure

equation of velocity and displacement is

V=−2x+4

acceleration a=V

dx

dv

=(−2x+4)(−2)

=4x−8

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