Question

A body is pivoted and a force of 20 N is applied at a distance of 60 cm from the pivot. The moment of the force is,​

Answer 1

Given,

• Force (F) = 20 N
• Distance (r) = 60 cm = 0.6 m

We know the equation:

$\boxed{\bold{\sf{Moment \ of \ Force =F\times r }}}$

Applying the values to the equation:

$\sf{\implies Moment \ of \ Force =20 \times 0.6 }$

$\sf{\implies Moment \ of \ Force =12 \ Nm }$

$\huge{\boxed{\bold{\sf{\therefore Moment \ of \ Force =12 \ N m }}}}$

Answer 2

Answer:

Answer is 12 Nm

Explanation:

Answer is 12 Nm