Physics, asked by Anonymous, 7 months ago

A body is pivoted at a point. A force of 10 N is
applied at a distance of 30 cm from the pivot.
Calculate the moment of force about the pivot.​

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Answers

Answered by Anonymous
53

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  • 3 Nm.

\huge{\purple{\underline{\underline{\bf{\pink{Explanation}}}}}}

Moment of force is calculated as:

Force x (perpendicular distance between point of application of force and axis of rotation)

But the unit should of the same system, SI or CGS

Here, Force = 10 N

Distance = 30/100 = 0.3 m

Hence, Moment of force = 10x0.3 Nm

= 3 Nm

Answered by Anonymous
5

\huge\underline{\underline{\bold{\red{A}\green{n}\pink{s}\orange{w}\blue{e}{r}}}}

3 Nm

Moment of force is calculated as:

Force x (perpendicular distance between point of application of force and axis of rotation)

But the unit should of the same system, SI or CGS

Here, Force = 10 N

Distance = 30/100 = 0.3 m

Hence, Moment of force = 10x0.3 Nm

= 3 Nm

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