Question

A body is pivoted at a point. A force of 10 N is applied at a distance of 30 cm form the pivot. Calculate the moment of force about the pivot.​

Answer 1

Answer:

torque=d×f

torque=0.3×10(100cm=1m)

torque=3

Answer 2

★ Given :

• ➼ Force (F) = 10 N

• ➼ Distance (r) = 30 cm = 0.3 m

★ Find :

• ➼ Moment of Force about the pivot.

★ Formula Used :

• ➼ Moment to force = F ༝ r

★ Solution :

• ➢ 10 ༝ 0.3

• ➢ 3 Nm

☯ Therefore,

• Hence, the moment of Force about the pivot is 3 Nm.

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