Question

A body is pivoted at a point, A force of 10 Newton is applied at a distance of 1.4 m from the pivot. Calculate the moment of force about the Pivot​

Answer 1

Answer:

$Given F=50N,r=60cm=0.6m</p><p>Moment \: of \: force =F×r</p><p>                           =50N×0.6m</p><p>                           =30Nm</p><p></p><p>$

Answer 2

Answer:

14 nf will be the answer

Explanation:

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