Physics, asked by rashmitaghosh5, 1 month ago

a body is pivoted at a point. A force of 15N is applied at a distance of 20cm from the Pivot. Calculate the moment of force.​

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Answered by sohamkdeb
1

Answer:

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Answered by Anonymous
9

Answer:

Given :-

  • A body is pivoted at a point. A force of 15 N is applied at a distance of 20 cm from the pivot.

To Find :-

  • What is the moment of force.

Formula Used :-

\clubsuit Moment Of Force Formula :

\mapsto \sf\boxed{\bold{\pink{Moment\: Of\: Force\: =\: Force \times Distance}}}

Solution :-

First, we have to convert the distance cm to m :

\implies \sf Distance =\: 20\: cm

\implies \sf Distance =\: \dfrac{2\cancel{0}}{10\cancel{0}}\: m

\implies \sf Distance =\: \dfrac{2}{10}\: m

\implies \sf\bold{\purple{Distance =\: 0.2\: m}}

Now, we have to find the moment of force :

Given :

  • Force = 15 N
  • Distance = 0.2 m

\longrightarrow \sf Moment\: Of\: Force =\: 15 \times 0.2

\longrightarrow \sf\bold{\red{Moment\: Of\: Force =\: 3\: Nm}}

{\small{\bold{\underline{\therefore\: The\: moment\: of\: force\: is\: 3\: Nm\: .}}}}

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