Question

A body is projected at an angle of 60° with horizontal,with a speed of 40m/s.The speed of the body when velocity becomes perpendivular to initial velocity is(g=10m/s²)

1.20√3m/s 2.40/√3m/s 3.20m/s 4.30m/s

Answer 1

Answer:

2 hoga

Explanation:

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Answer 2

Answer:

The speed of the body when velocity becomes perpendicular to initial velocity is 40/√3 ms⁻¹.

Explanation:

The initial velocity of the body $u= 40ms^{-1}$

The angle pf projectile with horizontal $=60^{o}$

From the relation:

     $vCos(90^{o}-\theta)= uCos\theta$

        $vSin\theta=uCos\theta$

  ∴          $v= u(\frac{Cos\theta}{Sin\theta})\\\\ v=ucot\theta \\ v=(40)Cot60^{o}\\ v=\frac{40}{\sqrt{3} } ms^{-1}$

Therefore the option (2) is correct.