Question

: A body is projected at time (t = 0) from a certain point on a planet surface with a certain velocity
at a certain angle with the planet's surface (assumed horizontal). The horizontal and vertical
displacement x and y in metre are related to time as x = 10/3t and y = 10t - 412
Then find the following
(0) Velocity after 1s

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Answer 1

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$\Large\fbox{\color{purple}{QUESTION}}$:

A body is projected at time (t = 0) from a certain

point on a planet surface with a certain velocity

at a certain angle with the planet's surface (

(assumed horizontal). The horizontal and

vertical

displacement x and y in metre are related to

time as x = 10/3t and y = 10t - 412

Then find the following

(0) Velocity after 1s

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$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

Differentiate y to get, vy=10−2t.

Thus maximum height means vy=0, or, t=5s.

Thus, for t=5, y=10×5−52=25m

$\Large\mathcal\green{FOLLOW \: ME}$

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Answer 2

Explanation:

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$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

Differentiate y to get, vy=10−2t.

Thus maximum height means vy=0, or, t=5s.

Thus, for t=5, y=10×5−52=25m

$\Large\mathcal\blue{FOLLOW \: ME}$

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