Question

A body is projected from height of 60m with a velocity 10 ms-1 at angle 30 degrees to horizontal the time of flight of the body is

Answer 1

apply 2usintheta by g hence
2×10sin 30 by 10
1

Answer 2

Hi friend,

We know the formula that
Time of flight =2u sin θ/ g

T=2×10×sin30° /60

T=20/120

T= 0.16666 secs .

Hope this helped you a little!!!