Question

a body is projected from the earth at an angle 30 with the horizontal with some initialvelocity. if its range is 20m the maximum height reached by it is

Answer 1

this is an excellent answer

Answer 2

$range = \frac{ {u}^{2} sin2 \alpha }{g} \\ \alpha = 30(given) \\ range = 20m(given) \\ so \\ 20 = \frac{ {u}^{2} \sin(60) }{ g} \\ 200 = {u}^{2} \sin(60) \\ {u}^{2} = \frac{200}{ \sin(60) } \\ \\ now \: maximum \: height \: = \frac{ {u}^{2} }{2g} \\ \frac{ \frac{200}{ \sin(60) } }{2g} \\ max \: height = \frac{10}{ \sin(60) } \\ \frac{20}{ \sqrt{3} } \\ 11.56m$
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