Question

A body is projected horizontally from the top of a hill with velocity of 19.6m/s. The time elaj
vertical component of velocity is thrice the horizontal component of its velocity is

Answer 1

Answer:

u

v

=0

v=9.8×2=19.6 m/s

a=−9.8m/s

2

v=u+at

9.8

19.6

=t⇒t=2 sec