A body is projected horizontally from the top of a tower with a velocity of 9.8 m/s find the time after which vertical velocity become double the horizontal velocity
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TIME = 2 SECOND
Solutions:-
- Initial
Hz Speed = 9.8m/s
Vt Speed = 0
- at time t
Hz Speed = 9.8m/d
Vt Speed = gt ( V = u + gt )
According to Question
gt = 2 × 9.8
t = 2 sec. g = 9.8m/s^2
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