Question

A body is projected horizontally from the top of a tower with 30m/s. Calculate the velocity of that body after 4 s.

Answer 1

Answer:

Vhorizontal ie Vxwill be constant so it will remain 30 while V vertical will increase by v=u+gt since u=0 so Vh = 10×4=40m/s so net velocity = root of Vx^2 + Vy^2 ie = 50 m/s