Question

A body is projected horizontally from the top of a tower of height 4.9 m with a velocs
9.8ms The velocity with which the body strikes the ground is
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Answer 1

Answer:

9.81m/s is the answer.

Explanation:

given, hmax = 4.9m

acceleration due to gravity=9.8m/s^2

u=0

velocity with which it will reach the ground=  v^2=u+2(G)(Hmax)

Now, v^2=2(9.8)(4.9)

v^2=2(48.2)

v^2=96.4

v=under root 96.4

v=9.81m/s

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Answer 2

Answer:9.8sqr2m/s

Explanation: