A body is projected horizontally from the top of the hill with 30 metre per second if ,g=10meter per second the velocity of the body after time t=4seconds
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h=?
u=?
t=4
v=30
g=10
v=u+gt
30=u+10×3
u=0
h=ut+1/2gt^2
=0×4+1/2×10×4×4
than
h=80m
u=?
t=4
v=30
g=10
v=u+gt
30=u+10×3
u=0
h=ut+1/2gt^2
=0×4+1/2×10×4×4
than
h=80m
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