Question

a body is projected horizontally from top of tower 100 m and velocity 9.8m/s ..find velocity with which hits ground

Answer 1

Hope my answer helps you.

I am sending the pic of my answer.

I have taken some approximations in the answer so the answer would be near to the required.

Answer 2

The velocity with which it hits ground is 45.34 m/s.

Explanation:

Given that,

Height of the tower, h = 100 m

Initial velocity of the body, u = 9.8 m/s

To find,

The velocity with which hits ground.

Solution,

Let v is the velocity velocity with which it hits the ground. It can be calculated using third equation of motion as :

$v^2-u^2=2gh$

$v^2=2gh+u^2$

$v^2=2\times 9.8\times 100+(9.8)^2$

v = 45.34 m/s

So, the velocity with which it hits ground is 45.34 m/s.

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Third equation of motion

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