A body is projected horizontally with a velocity 23m/s from a height of 5m. What is the velocity of the body on reaching the ground?
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Answer:
25 m/sec
Explanation:
horizontal component of velocity is always
constant during the motion
Vx= constant = 23 m/sec
calculation of vertical component of vel:-(Vy)
given. Uy= 0 , h= 5m g= 10m/sec² (say)
since Vy²= Uy²+2gh
= 0²+2×10×5= 100
=> Vy= √100= 10 m/ sec²
=> V= √ (Vx²+Vy²)
= √ ( 23)²+(10)²
= √(529+100)
= √629
= 25m/sec ( approximately)
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