Question

A body is projected horizontally with speed 20m/s what will be its spedd atr 5 sec

Answer 1

Hey mate ^_^

Since, body is projected horizontally with a velocity of 20m/s.

ux = 20m/s

ax = 0

So,

vx = 20m/s for all time.

Along vertical axis,

uy = 0

t = 5

ay = 10m/s^2

vy =?

vy = uy +ayt

vy = 0 + 10*5= 50m/s

So, magnitude of velocity of body after 5s

√{(50)²+(20)²}m/s
=√2900 m/s
=53.851 m/s
= 54 m/s (approx)

#Be Brainly❤️

Answer 2

Initial speed u=20m/s
As it is horizontally projected all the speed is as x-component.
Since there is no force in x-direction, the speed shall remain constant.
After 5sec, speed in y-axis will be,
v=0+(10)5
v=50m/s
So velocity of body will be 20i-50j
Speed will be 10√29m/s


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