Question

a body is projected horizontally with speed 5m/s from height h takes 8s to reach ​

Answer 1

DISTANCE=SPEED×TIME

DISTANCE=5×8

DISTANCE=40 M/S

BTS FOREVER

Answer 2

CORRECT QUESTION:

A body is projected horizontally with speed 5m/s from height h takes 8s to reach the ground. Calculate the range of the Projectile .

Diagram:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\linethickness{0.4mm}\qbezier(0,5)(5,4.5)(5,0)\put(0,0){\line(0,1){5}}\put(-1,0){\line(1,0){7}}\put(0,5){\vector(1,0){3.5}}\multiput(-0.5,0)(0.5,0){13}{\qbezier(0,0)(0,0)(-0.3,-0.3)}\put(-1,2.5){\bf{H}}\put(4,4.9){ \bf{v_x=5\: m/s} }\put(2.3,-1){\bf{R}}\end{picture}$

Calculation:

This is an example of Height-ground Projectile. In this case, the range of the projectile can be calculated by multiplying the x axis velocity component of the object with the time taken to reach the ground.

Let range be R :

$\therefore \: R = v_{x} \times t$

$\implies\: R = 5 \times 8$

$\implies\: R = 40 \: m$

So, range of Projectile is 40 m.

Additional Information:

• While calculating the time taken to each ground in these kind of projectiles , you need to use the Y axis component of velocity , which will be zero m/s.

• General expression for range : R = v_(x) × √(2h/g) .

Hope It Helps.