Question

. Find the values of y for which the distance between the points P(2.-3) and Q(10,y) is
10 units​

Answer 1

Answer:

cant understand actually

Step-by-step explanation:

in the basis of phyics the mass of the string in the theory of matter states that idk

Answer 2

Step-by-step explanation:

Distance between two points =

$\sqrt{ ({y1 - x1})^{2} + {(y2 - x2)}^{2} }$

$10 = \sqrt{ {(10 - 2)}^{2} + {(y + 3)}^{2} }$

$10 = \sqrt{64 + {(y + 3)}^{2} }$

Squaring both the sides, we get

$100 = 64 + {(y + 3)}^{2}$

$36 = {(y + 3)}^{2}$

putting square root both the sides,we get

6 = y+3. or. -6 = y+3

So,we get the value of y = 3 or -9