a body is projected in the air that the horizontal range covered by the body is equal to the maximum vertical height attained by the body during the motion find the angle of projection
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HELLO ,
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Given that H= R
H = u2 sin2 θ /2g
R = u2sin 2 θ /g
so, u2 sin2 θ /2g = u2sin 2 θ /g
as sin 2θ = 2 sinθ cosθ
so u2 sin2 θ /2g = 2u2sinθcosθ /g
we get tan θ = 4
or, θ= tan-1 (4)
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Hope it helps u! !!!
# Nikky
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Given that H= R
H = u2 sin2 θ /2g
R = u2sin 2 θ /g
so, u2 sin2 θ /2g = u2sin 2 θ /g
as sin 2θ = 2 sinθ cosθ
so u2 sin2 θ /2g = 2u2sinθcosθ /g
we get tan θ = 4
or, θ= tan-1 (4)
_____________________
Hope it helps u! !!!
# Nikky
aditya2404:
btw where are u from
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